33x^2-61x+26=0

Solution for 33x^2-61x+26=0 equation:

33x^2-61x+26=0

a = 33; b = -61; c = +26;
Δ = b2-4ac
Δ = -612-4·33·26
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-17}{2*33}=\frac{44}{66}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+17}{2*33}=\frac{78}{66}
=1+2/11
$